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(B) To synthesize the dipeptide $Phe-Ala$,we need to couple the carboxyl group of $Phe$ with the amino group of $Ala$.$1$. The $N$-terminus of $Phe$ m

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$(3)$ and $(2)$

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(B) To synthesize the dipeptide $Phe-Ala$,we need to couple the carboxyl group of $Phe$ with the amino group of $Ala$.$1$. The $N$-terminus of $Phe$ must be protected,and its $C$-terminus must be free. Thus,we use $ZNH-CH(CH_2C_6H_5)-COOH$ (reagent $(3)$).$2$. The $C$-terminus of $Ala$ must be protected,and its $N$-terminus must be free. Thus,we use $H_2N-CH(CH_3)-COOCH_2C_6H_5$ (reagent $(2)$).$3$. Coupling these two reagents followed by deprotection yields $Phe-Ala$.

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